d^2+14d+28=0

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Solution for d^2+14d+28=0 equation:


Simplifying
d2 + 14d + 28 = 0

Reorder the terms:
28 + 14d + d2 = 0

Solving
28 + 14d + d2 = 0

Solving for variable 'd'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + 14d + -28 + d2 = 0 + -28

Reorder the terms:
28 + -28 + 14d + d2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 14d + d2 = 0 + -28
14d + d2 = 0 + -28

Combine like terms: 0 + -28 = -28
14d + d2 = -28

The d term is 14d.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14d + 49 + d2 = -28 + 49

Reorder the terms:
49 + 14d + d2 = -28 + 49

Combine like terms: -28 + 49 = 21
49 + 14d + d2 = 21

Factor a perfect square on the left side:
(d + 7)(d + 7) = 21

Calculate the square root of the right side: 4.582575695

Break this problem into two subproblems by setting 
(d + 7) equal to 4.582575695 and -4.582575695.

Subproblem 1

d + 7 = 4.582575695 Simplifying d + 7 = 4.582575695 Reorder the terms: 7 + d = 4.582575695 Solving 7 + d = 4.582575695 Solving for variable 'd'. Move all terms containing d to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + d = 4.582575695 + -7 Combine like terms: 7 + -7 = 0 0 + d = 4.582575695 + -7 d = 4.582575695 + -7 Combine like terms: 4.582575695 + -7 = -2.417424305 d = -2.417424305 Simplifying d = -2.417424305

Subproblem 2

d + 7 = -4.582575695 Simplifying d + 7 = -4.582575695 Reorder the terms: 7 + d = -4.582575695 Solving 7 + d = -4.582575695 Solving for variable 'd'. Move all terms containing d to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + d = -4.582575695 + -7 Combine like terms: 7 + -7 = 0 0 + d = -4.582575695 + -7 d = -4.582575695 + -7 Combine like terms: -4.582575695 + -7 = -11.582575695 d = -11.582575695 Simplifying d = -11.582575695

Solution

The solution to the problem is based on the solutions from the subproblems. d = {-2.417424305, -11.582575695}

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